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JEE MATHEMATICS MCQ: RATE MEASURE

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A particle is moving in a straight line such that the distance described ‘

s

’ and the time taken ‘

t

’ are given by

t = a{s^2} + bs + c,a > 0.

If

v

is the velocity of the particle at any time

t

, then acceleration is

View answer and explanation

Correct option: C

- 2a{v^3}

Option C (

-2a{v^3}

) is correct because it is derived by differentiating the given equation with respect to time and solving for the acceleration (dv/dt).

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