JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Analyzing +4 | -1

(1+a)\left(1+a^2\right)\left(1+a^4\right) \ldots\left(1+a^{128}\right)=\sum\limits_{{r=0}}^n a^r

, then

n

is equal to

View answer and explanation

Correct option: A

255

Option A (255) is correct because the product expands to a sum of powers of 'a' up to

a^{255}

, making n = 255.

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