JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1

Find the range of

f(x)=1+3 \cos 2 x

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Correct option: C

[-2,4]

Option C ([-2,4]) is correct because the range of the cosine function is [-1, 1], and this is used to find the range of the given function.

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

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f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}