NEET UG CHEMISTRY MCQ: CHEMICAL KINETICS

1 Hard

1 of 1

Application +4 | -1

The rate law for a reaction between the substances

A

and

B

is given by

rate = k{\left[ A \right]^n}{\left[ B \right]^m}

. On doubling the concentration of

A

and halving the concentration of

B

, the ratio of the new rate to the earlier rate of the reaction will be as

View answer and explanation

Correct option: D

{2^{\left( {n - m} \right)}}

Option D (

{2^{\left( {n - m} \right)}}

) is correct because doubling [A] raises the rate by

2^n

and halving [B] reduces the rate by

(1/2)^m

, resulting in a ratio of

2^n / (1/2)^m = 2^(n+m)

. However, the question asks for ratio of new rate to the earlier rate, which is

2^n * (1/2)^m = 2^(n-m)

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