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JEE PHYSICS MCQ: ELECTROMAGNETIC WAVES

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If electric field in an electromagnetic wave is given by E=6×106sin⁡(2πft−2πλx)VmE=6 \times 10^6 \sin \left(2 \pi f t-\frac{2 \pi}{\lambda} x\right) \frac{\mathrm{V}}{\mathrm{m}}. The peak value of magnetic field in the region is
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Correct option: D
0.02 T0.02 \mathrm{~T}
Option D (0.02 T0.02 \mathrm{~T}) is correct because it is calculated using the relationship between the electric field and magnetic field in an electromagnetic wave, E0/B0=cE_0/B_0 = c.

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