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JEE MATHEMATICS MCQ: LIMITS

1 Hard
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Application +4 | -1
Let f:R→Rf:R \to R be a differentiable function such that f(2)=2f\left( 2 \right) = 2. Then, the value of lim⁡x→2∫2f(x)4  t3x−2dt\lim\limits_{x \to 2} \int \limits_2^{f\left( x \right)} \frac{{4\;{t^3}}}{{x - 2}}dt, is
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Correct option: C
32f′(2)32f'\left( 2 \right)
Option C (32f′(2)32f'(2)) is correct because it is the result of applying L'Hopital's rule and the fundamental theorem of calculus to the given limit.

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