NEET UG PHYSICS MCQ: WAVES

1 Medium

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Application +4 | -1

A wire of density

9 \times {10^3}kg{m^{ - 3}}

is stretched between two clamps

1

m part and is subjected to an extension of

4.9 \times {10^{ - 4}}m

. The lowest frequency of transverse vibration in the wire is

Y = 9 \times {10^{10}}N{m^{ - 2}})

View answer and explanation

Correct option: B

35\mathrm{ }\,\,Hz

Option B (

35\mathrm{ }\,\,Hz

) is correct because it is the calculated fundamental frequency of the stretched wire using the given parameters.

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