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JEE PHYSICS MCQ: MOTION IN A STRAIGHT LINE

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A point particle starting from rest has a velocity that increase linearly with time such that v=pt, where p=4ms−2p = 4\mathrm{m}{\mathrm{s}^{ - 2}}. The distance covered in the first 2 s will be
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Correct option: C
8 m
Option C (8 m) is correct because the distance is calculated by integrating the velocity function v=pt with respect to time from 0 to 2 seconds.

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