JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1

\frac{1}{2} \operatorname{cosec}^2 \theta, 2 \cot \theta, \sec \theta, 0<\theta<\frac{\pi}{2}

are in GP, then

\theta

is equal to

View answer and explanation

Correct option: C

\frac{\pi}{3}

Option C (

\frac{\pi}{3}

) is correct because solving the GP condition leads to

\cos \theta = \frac{1}{2}

, which corresponds to

\theta = \frac{\pi}{3}

More Questions from SEQUENCE OF SERIES

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\log \left(\frac{a}{3 b}\right)

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\frac{3}{4}