$C{H_3} - C \equiv CH\xrightarrow[{HgS{O_4}}]{{{H_2}S{O_4}}}A\xrightarrow[{}]{{{\text{Isomerisation}}}}C{H_3} - \mathop C\limits_{\begin{array}{*{20}{c}} {||} \\ O \end{array}} - C{H_3}$ Structure of $A$ and type of isomerism in the above reactions respectively.

JEE CHEMISTRY MCQ: HYDROCARBONS

1 Medium

1 of 1

Application +4 | -1

C{H_3} - C \equiv CH\xrightarrow[{HgS{O_4}}]{{{H_2}S{O_4}}}A\xrightarrow[{}]{{{\text{Isomerisation}}}}C{H_3} - \mathop C\limits_{\begin{array}{cccccccccccccccccccc} {||} \\ O \end{array}} - C{H_3}

Structure of

A

and type of isomerism in the above reactions respectively.

View answer and explanation

Correct option: C

Prop-1-en-2-ol, Tautomerism

Option C (Prop-1-en-2-ol, Tautomerism) is correct because the intermediate A is prop-1-en-2-ol, which then undergoes tautomerism to form acetone.