$C{H_3} - \begin{array}{*{20}{c}} {C{H_3}} \\ | \\ C \\ | \\ {C{H_3}} \end{array} - Br + KOH\left( {aq} \right) \to C{H_3} - \begin{array}{*{20}{c}} {C{H_3}} \\ | \\ C \\ | \\ {C{H_3}} \end{array} - OH + KBr$ Above reaction is

JEE CHEMISTRY MCQ: HALOALKANES AND HALO ARENES

1 Easy

1 of 1

Analyzing +4 | -1

C{H_3} - \begin{array}{cccccccccccccccccccc} {C{H_3}} \\ | \\ C \\ | \\ {C{H_3}} \end{array} - Br + KOH\left( {aq} \right) \to C{H_3} - \begin{array}{cccccccccccccccccccc} {C{H_3}} \\ | \\ C \\ | \\ {C{H_3}} \end{array} - OH + KBr

Above reaction is

View answer and explanation

Correct option: A

S{N^1}

Option A is correct because the reaction proceeds via a SN1 mechanism due to the formation of a stable tertiary carbocation intermediate.