JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

|x| < 1

, and

r

th term of a series is

1+x

+x^2+\ldots+x^{r-1}

, then sum to

n

terms of the series is

View answer and explanation

Correct option: B

\frac{n-(n+1) x+x^{n+1}}{(1-x)^2}

Option B (

\frac{{n-(n+1) x+x^{{n+1}}}}{{(1-x)^2}}

) is correct because it is the result of summing the given series using the formula for a geometric series.

More Questions from SEQUENCE OF SERIES

Practice All Chapter MCQs →

A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

(B \cup C)-A

a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

Q(y)=a_0+a_1 y+\ldots+a_{2012} y^{2012}

y=x-2

\sum\limits_{{i=0}}^{2012} a_i

\log \left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)

\log \left(\frac{a}{3 b}\right)

A P

a, b

G P

a, b, c

\frac{3}{4}