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JEE MATHEMATICS MCQ: LIMITS

1 Easy
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Application +4 | -1
Value of lim⁡x→0ℓn(1+2x−3x2+4x3)ℓn(1−5x+6x2−7x3)\lim \limits_{{x \rightarrow 0}} \frac{\ell n \left(1+2 x-3 x^2+4 x^3\right)}{\ell n \left(1-5 x+6 x^2-7 x^3\right)} is -
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Correct option: C
−25-\frac{2}{5}
Option C (-2/5) is correct because the limit is evaluated using L'Hopital's rule or by manipulating the logarithmic expressions.

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