If $\log _{0.3}(x-1)<\log _{0.09}(x-1),$ then $x$ lies in the interval

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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\log _{0.3}(x-1)<\log _{0.09}(x-1),

then

x

lies in the interval

View answer and explanation

Correct option: C

(2, \infty)

Option C ((2, ∞)) is correct because solving the logarithmic inequality leads to x > 2, which corresponds to the interval (2, infinity).

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\sum\limits_{{i=0}}^{2012} a_i

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A P

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G P

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\frac{3}{4}