The total number of protons in $8.4 \mathrm{~g}$ of $\mathrm{MgCO}_3$ is $\left(N_{\mathrm{A}}=6.02 \times 10^{23}\right)$

JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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The total number of protons in

8.4 \mathrm{~g}

\mathrm{MgCO}_3

\left(N_{\mathrm{A}}=6.02 \times 10^{23}\right)

View answer and explanation

Correct option: B

2.52 \times 10^{24}

Option B (

2.52 \times 10^{24}

) is correct because it is the total number of protons in 8.4 g of MgCO₃, calculated by determining the number of moles of MgCO₃ and the number of protons per molecule.

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