A convex lens is placed between object and a screen. The size of object is ${\rm{3}}\,\,{\rm{cm}}$ and an image of height ${\rm{9}}\,\,{\rm{cm}}$ is obtained on the screen. When the lens is displaced to a new position, what will be the size of image on the screen?

NEET UG PHYSICS MCQ: RAY OPTICS

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A convex lens is placed between object and a screen. The size of object is

\mathrm{3}\,\,\mathrm{cm}

and an image of height

\mathrm{9}\,\,\mathrm{cm}

is obtained on the screen. When the lens is displaced to a new position, what will be the size of image on the screen?

View answer and explanation

Correct option: D

\mathrm{1}\,\,\mathrm{cm}

The correct answer is D (

\mathrm{1}\,\,\mathrm{cm}

) because when the lens is displaced, the object and image positions are interchanged, and the magnification becomes the inverse.

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