The maximum work done in expanding 16 g oxygen at 300 K and occupying a volume of $5\,\,{\rm{d}}{{\rm{m}}^3}$ isothermally until the volume become $25\,\,{\rm{d}}{{\rm{m}}^3}$ is:

$ + 2.81 \times {10^3}{\rm{J}}$

$2.01 \times {10^{ - 3}}{\rm{J}}$

$ + 2.01 \times {10^{ - 6}}{\rm{J}}$

NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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Application +4 | -1

The maximum work done in expanding 16 g oxygen at 300 K and occupying a volume of

5\,\,\mathrm{d}{\mathrm{m}^3}

isothermally until the volume become

25\,\,\mathrm{d}{\mathrm{m}^3}

is:

View answer and explanation

Correct option: A

2.01 \times {10^3}\mathrm{J}

Option A (

2.01 \times {10^3}\mathrm{J}

) is correct because it is the maximum work done calculated using the isothermal reversible expansion formula.

Practice All Chapter MCQs →

{T_i}

{T_f}

\mathrm{H}_2 \mathrm{O}(\mathrm{s}) \rightarrow \mathrm{H}_2 \mathrm{O}(\mathrm{g})

\mathrm{X}_2 \mathrm{O_4(l}) \longrightarrow 2 \mathrm{XO}_2(\mathrm{g}), \Delta U=2.1 \mathrm{~kcal}, \Delta S=20 \mathrm{~cal} \mathrm{~K}^{-1}

300 \mathrm{~K}

\Delta G