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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy
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Application +4 | -1
The value of ∫−ππcos⁡2x1+axdx,a>0\int\limits_{{-\pi}}^\pi \frac{\cos ^2 x}{1+a^x} d x, a > 0, is
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Correct option: C
π/2\pi / 2
Option C (π/2\pi / 2) is correct because by using the property ∫0af(x)dx=∫0af(x)+f(−x)dx\int_0^a f(x) dx = \int_0^a {f(x) + f(-x)} dx, the integral simplifies to ∫0πcos⁡2xdx\int_0^\pi \cos^2 x dx, which evaluates to π/2\pi/2.

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