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JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1
If f(x+2y,x−2y)=xyf(x+2 y, x-2 y)=x y, then f(x,y)f(x, y) equals
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Correct option: A
x2−y28\frac{x^2-y^2}{8}
Option A (x2−y28\frac{{x^2-y^2}}{{8}}) is correct because it is obtained by substituting xx and yy in terms of uu and vv in the given functional equation.

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