NEET UG PHYSICS MCQ: NUCLEI

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Analyzing +4 | -1

Given the masses of various atomic particles

{m_p} = 1.0072\,u,\,\,\,\,{m_n} = 1.0087\,\,u,\,\,\,\,{m_e} = 0.000548\,\,u,\,\,\,\,{m_{\bar v}} = 0,\,\,\,\,{m_d} = 2.0141\,\,u,

Where

p

= proton,

n

= neutron,

e

= electron

\bar v =

antineutrino and

d

= deuteron. Which of the following process is allowed by momentum and energy conservation?

View answer and explanation

Correct option: C

n + p \to d + \bar v

Option B (

p \to n + {e^ + } + \bar v

) is correct because it is the only option that violates energy conservation, making it not allowed.

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