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NEET UG PHYSICS MCQ: MAGNETISM AND MATTER

1 Hard
1 of 1
Application +4 | -1
A dip circle shows an apparent dip of 45∘45^\circ at a place where the true dip is 30∘30^\circ. If the dip circle is rotated through 90∘90^\circ, what apparent dip will it show:
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Correct option: A
cot⁡−1(2){\cot ^{ - 1}}\left( {\sqrt 2 } \right)
Option A (cot⁡−1(2){\cot ^{ - 1}}\left( {\sqrt 2 } \right)) is correct because the apparent dip changes when the dip circle is rotated, and the new apparent dip can be calculated using the given formula.

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