NEET UG PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

1 Hard

1 of 1

Application +4 | -1

During an experiment, an ideal gas is found to obey an additional law

V{P^2} = {\text{constant}}{\text{.}}

The gas is initially at temperature

T

and volume

V.

The temperature of the gas when it expands to a volume

2V

View answer and explanation

Correct option: C

\sqrt 2 \,T

Option C (

\sqrt 2 \,T

) is correct because using the ideal gas law and the given condition

VP^2 = constant

, we can relate the initial and final states to find the new temperature.

More Questions from THERMAL PROPERTIES OF MATTER

Practice All Chapter MCQs →

60 \mathrm{~cm} \times 50 \mathrm{~cm} \times 20 \mathrm{~cm}

1 \mathrm{~cm}

0^{\circ} \mathrm{C}

40^{\circ} \mathrm{C}

3.4 \times 10^5 \mathrm{~J} \mathrm{~kg}^{-1}

\left. {0.05{\text{W}}{{\text{m}}^{ - 1}}^\circ {{\text{C}}^{ - 1}}} \right)

2 \times 10^5 \mathrm{~J} / \mathrm{sm}^2

127^{\circ} \mathrm{C}

32 \times 10^5 \mathrm{~J} / \mathrm{s}-\mathrm{m}^2

\sigma

+ \frac{1}{2}