Skip to main content
Back to THERMODYNAMICS

NEET UG PHYSICS MCQ: THERMODYNAMICS

1 Easy
1 of 1
Application +4 | -1
For a refrigerator, heat absorbed from source is 800 J800 \mathrm{~J} and heat supplied to sink is 500 J500 \mathrm{~J} then find coefficient of performance.
View answer and explanation
Correct option: C
53\frac{5}{3}
Option C (53\frac{5}{3}) is correct because the coefficient of performance (COP) for a refrigerator is the ratio of heat absorbed from the cold reservoir to the work done.

More Questions from THERMODYNAMICS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.