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JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

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The number of electron in 3.1 mg NO3−3.1 \mathrm{~mg} \mathrm{~NO}_3^{-} is:-
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Correct option: C
9.6×10209.6 \times 10^{20}
Option C (9.6 × 1020) is correct because the number of electrons is calculated by finding the moles of NO₃⁻, then multiplying by Avogadro's number and the number of electrons in the ion.

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