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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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Application +4 | -1
When a certain metal was irradiated with light of frequency 4.0×1016 s−14.0 \times 10^{16} \mathrm{~s}^{-1}, the photoelectrons emitted has three times the kinetic energy as the kinetic energy of photoelectrons emitted when the metal was irradiated with light of frequency 2.0×1016 s−12.0 \times 10^{16} \mathrm{~s}^{-1} Calculate the critical frequency (v0)\left(v_0\right) of the metal.
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Correct option: B
1×1016 s−11 \times 10^{16} \mathrm{~s}^{-1}
Option B (1×1016 s−11 \times 10^{16} \mathrm{~s}^{-1}) is correct because it is the critical frequency calculated using Einstein's photoelectric equation and the given conditions.

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