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JEE MATHEMATICS MCQ: PAIR OF STRAIGHT LINES

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Analyzing +4 | -1
To the lines ax2+2hxy+by2=0a x^2+2 h x y+b y^2=0 the lines a2x2+2h(a+b)xy+b2y2=0a^2 x^2+2 h(a+b) x y+b^2 y^2=0 are
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Correct option: A
equally inclined
Option A (equally inclined) is correct because the angle bisectors of both pairs of lines are the same, indicating they are equally inclined.

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If ax2+2hxy+by2+2gx+2fy+c=0a x^2+2 h x y+b y^2+2 g x+2 f y+c=0 represents parallel straight lines, then Image of the point (−1,3)(-1,3) with respect to the line y=2xy=2 x is If the pair of lines represented by ax2+2hxy+by2+2gx+2fy+c=0a x^2+2 h x y+b y^2+2 g x+2 f y+c=0 intersect on yy-axis, then If the sum of the slopes of the lines given by 4x2+2λxy−7y2=04 x^2+2 \lambda x y-7 y^2=0 is equal to the product of the slopes, then λ\lambda is equal to The equation 3x2+2hxy+3y2=03 x^2+2 h x y+3 y^2=0 represents a pair of straight lines passing through the origin. The two lines are The value of hh for which 3x2−3hxy+4y2=03 x^2-3 h x y+4 y^2=0 represents a pair of coincident lines are
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