JEE MATHEMATICS MCQ: SCALAR TRIPLE PRODUCT

1 Medium

1 of 1

Analyzing +4 | -1

|\bar{a}|=1,|\bar{b}|=2,|\bar{c}|=3

and

\bar{a}, \bar{b}

are perpendicular to

\bar{c}

and

\bar{a} \cdot \bar{b}=1,(\bar{a}, \bar{b}, \bar{c}

form a vector traid in R.H.S) then

\left[\frac{\bar{a} \times \bar{b}}{5} \quad \bar{b} \times \bar{c} \frac{\bar{a}+\bar{b}+\bar{c}}{\sqrt{3}}\right]=

View answer and explanation

Correct option: C

Option C (3) is correct because the scalar triple product simplifies to 3 after applying vector identities and given conditions.

More Questions from SCALAR TRIPLE PRODUCT

Practice All Chapter MCQs →

\vec r\cdot\vec a = \vec r\cdot\vec b = \vec r\cdot\vec c = 0

\vec r,

\left[ {\vec a\vec b\vec c} \right],

\frac{{x - 3}}{2} = \frac{{y - 2}}{3} = \frac{{z - 1}}{{ - 1}}

\frac{{x + 3}}{2} = \frac{{y - 6}}{1} = \frac{{z - 5}}{3},

\mathbf{\vec a} = \widehat \mathbf{i} - \mathbf{\hat k},\;\mathbf{\vec b} = x\widehat \mathbf{i} + \widehat \mathbf{j} + \left( {1 - x} \right)\mathbf{\hat k}

\mathbf{\vec c} = y\widehat \mathbf{i} + x\widehat \mathbf{j} + \left( {1 + x - y} \right)\mathbf{\hat k}.

\left[ {\mathbf{\vec a},\;\mathbf{\vec b},\;\mathbf{\vec c}} \right]

\vec{a}, \vec{b}

((\vec{a} \times \vec{b}) \times \vec{a}) \cdot((\vec{b} \times \vec{a}) \times \vec{b})

a \cdot(a \times b)=

\mathbf{r}=\mathbf{b}+\lambda \mathbf{c}