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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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Application +4 | -1
If point charges Q1=2×10−7CQ_1=2 \times 10^{-7} \mathrm{C} and Q2=3×10−7CQ_2=3 \times 10^{-7} \mathrm{C} are at 30 cm30 \mathrm{~cm} separation, then find electrostatic force between them
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Correct option: B
6×10−3 N6 \times 10^{-3} \mathrm{~N}
Option B (6×10−3 N6 \times 10^{-3} \text{ N}) is correct because it is the electrostatic force calculated using Coulomb's law.

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