JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

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Application +4 | -1

\int\limits_{0}^1 \frac{\sin t}{1+t} d t=\alpha

, then the value of the integral

\int\limits_{{4 \pi-2}}^{4 \pi} \frac{\sin \frac{t}{2}}{4 \pi+2-t} d t

in terms of

\alpha

is given by

View answer and explanation

Correct option: D

-\alpha

Option D (

-\alpha

) is correct because after substitution and simplification, the integral becomes the negative of the given integral.

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