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JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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Application +4 | -1

A wheel is subjected to uniform angular acceleration about its axis. Initially its angular velocity is zero. In the first 2 sec, it rotates through an angle

{\theta _1}

. In the next 2 sec, it rotates through an additional angle

{\theta _2}

. The ratio of

{\theta _2}/{\theta _1}

is

View answer and explanation

Correct option: C

3

Option C (3) is correct because the ratio of the additional angle to the first angle is calculated using the equations of rotational motion, resulting in 3.

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It is easier for a swimmer jumping into water from a height to describe a loop in the air by A uniform thin rod

\mathrm{AB}

\mathrm{L}

has linear mass density

\mu(x)=a+\frac{b x}{L}

x

is measured from

\mathrm{A}

\mathrm{CM}

of the rod lies at a distance of

\left(\frac{7}{12}\right) \mathrm{L}

\mathrm{A}

\mathrm{b}

are related as : A solid metal ring and a disc of same radius and mass are rotating about their diameters with same angular frequency. The ratio of their respective rotational kinetic energy values is When a torque acting upon a system is zero, then which of the following will be constant A point particle of mass

1.0 \mathrm{~g}

is rotating in a circle of diameter

8 \mathrm{~cm}

. Its moment of inertia will be The angular velocity of a particle is given by

\omega = {t^4} + 2{t^3}

then its angular acceleration of the particle at

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)