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NEET UG PHYSICS MCQ: ALTERNATING CURRENT

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An inductor of inductance L and resistor of resistance R are joined in series and connected by a source of frequency ω. Power dissipated in the circuit is
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Correct option: B
V2R(R2+ω2L2)\frac{{{V^2}R}}{{\left( {{R^2} + {\omega ^2}{L^2}} \right)}}
Option B (V2R(R2+ω2L2)\frac{{{V^2}R}}{{\left( {{R^2} + {\omega ^2}{L^2}} \right)}}) is correct because it represents the power dissipated in an RL circuit connected to an AC source.

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