JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1

Three distinct numbers

a_1, a_2, a_3

are in increasing G.P.

a_1^2+a_2^2+a_3^2=364

and

a_1+a_2+a_3=26

, then the value of

a_{10}

a_n

is the

n^{\text {th }}

term of the given G.P. is:

View answer and explanation

Correct option: A

2.3^9

Option A (

2.3^9

) is correct because it is the 10th term of the G.P. with first term 2 and common ratio 3, derived from the given equations.

More Questions from SEQUENCE OF SERIES

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A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

(B \cup C)-A

a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

Q(y)=a_0+a_1 y+\ldots+a_{2012} y^{2012}

y=x-2

\sum\limits_{{i=0}}^{2012} a_i

\log \left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)

\log \left(\frac{a}{3 b}\right)

A P

a, b

G P

a, b, c

\frac{3}{4}