JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

x^2+y^2=1

, then

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Correct option: B

y y^{\prime \prime}+\left(y^{\prime}\right)^2+1=0

Option B (y y'' + (y')² + 1 = 0) is correct because it is the result of differentiating the given equation twice and simplifying.

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