The equilibrium constants of the following are. ${{\rm{N}}_2} + 3{{\rm{H}}_{\rm{2}}}\leftrightharpoons2{\rm{N}}{{\rm{H}}_3}{\rm{ }}{{\rm{K}}_1}$ ${{\rm{N}}_{\rm{2}}}{\rm{ + }}{{\rm{O}}_{\rm{2}}}\leftrightharpoons{\rm{2NO }}{{\rm{K}}_2}$ ${{\rm{H}}_{\rm{2}}}{\rm{ + }}\frac{{\rm{1}}}{{\rm{2}}}{{\rm{O}}_{\rm{2}}} \to {{\rm{H}}_{\rm{2}}}{\rm{O }}{{\rm{K}}_3}$ The equilibrium constant $(K)$ of the reaction $2{\rm{N}}{{\rm{H}}_3}{\rm{ + }}\frac{5}{2}{{\rm{O}}_2}\overset K \leftrightarrows {\rm{2NO + 3}}{{\rm{H}}_2}{\rm{O,}}$ will be

JEE CHEMISTRY MCQ: Equilibrium

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The equilibrium constants of the following are.

{\mathrm{N}_2} + 3{\mathrm{H}_\mathrm{2}}\leftrightharpoons2\mathrm{N}{\mathrm{H}_3}\mathrm{ }{\mathrm{K}_1}

{\mathrm{N}_\mathrm{2}}\mathrm{ + }{\mathrm{O}_\mathrm{2}}\leftrightharpoons\mathrm{2NO }{\mathrm{K}_2}

{\mathrm{H}_\mathrm{2}}\mathrm{ + }\frac{\mathrm{1}}{\mathrm{2}}{\mathrm{O}_\mathrm{2}} \to {\mathrm{H}_\mathrm{2}}\mathrm{O }{\mathrm{K}_3}

The equilibrium constant

(K)

of the reaction

2\mathrm{N}{\mathrm{H}_3}\mathrm{ + }\frac{5}{2}{\mathrm{O}_2}\overset K \leftrightarrows \mathrm{2NO + 3}{\mathrm{H}_2}\mathrm{O,}

will be

View answer and explanation

Correct option: C

{K_2}K_3^3/{K_1}

Option C is correct. The equilibrium constant K is calculated by combining the given reactions to match the target reaction and then multiplying/dividing the corresponding equilibrium constants.

JEE CHEMISTRY MCQ: Equilibrium

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