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JEE MATHEMATICS MCQ: BINOMIAL THEOREM

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Application +4 | -1
If nn is even, then the middle term in the expansion of (x2+1x)n{\left( {{x^2} + \frac{1}{x}} \right)^n} is 924 x6{x^6}, then nn is equal to
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Correct option: B
12
Option B (12) is correct because the middle term in the expansion of (x2+1x)n{\left( {{x^2} + \frac{1}{x}} \right)^n} is given as 924x6{x^6}, and solving for n yields n=12.

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