JEE MATHEMATICS MCQ: THEORY OF EQUATION

1 Easy

1 of 1

Analyzing +4 | -1

Let

\alpha, \beta, \gamma

be the roots of the equation

(x-a)(x-b)(x-c)=d, d \neq 0

, the roots of the equation

(x-\alpha)(x-\beta)(x-\gamma)+d=0

are

View answer and explanation

Correct option: C

a, b, c

Option C (

a, b, c

) is correct because by substituting the roots of the first equation into a modified second equation, we find that

a, b,

and

c

are the roots.

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