If ${a_1},{a_2},{a_3}, \ldots ,{a_n}$ are the $n$ arithmetic means between $a$ and $b$, then $2\mathop \sum \limits_{i = 1}^n {a_i}$ equals

$\frac{{\left( {a + b} \right)}}{n}$

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Understanding +4 | -1

{a_1},{a_2},{a_3}, \ldots ,{a_n}

are the

n

arithmetic means between

a

and

b

, then

2\sum \limits_{i = 1}^n {a_i}

equals

View answer and explanation

Correct option: B

n\left( {a + b} \right)

Option B (

n\left( {a + b} \right)

) is correct because the sum of n arithmetic means between a and b is n times the average of a and b.

Practice All Chapter MCQs →

A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

(B \cup C)-A

a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

Q(y)=a_0+a_1 y+\ldots+a_{2012} y^{2012}

y=x-2

\sum\limits_{{i=0}}^{2012} a_i

\log \left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)

\log \left(\frac{a}{3 b}\right)

A P

a, b

G P

a, b, c

\frac{3}{4}