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NEET UG PHYSICS MCQ: WORK-ENERGY-POWER

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Application +4 | -1
A body of mass m accelerates uniformly from rest to v1{v_1} in time t1{t_1}. As a function of time t, the instantaneous power delivered to the body is
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Correct option: D
mv12tt12\frac{{mv_1^2t}}{{t_1^2}}
Option D (mv12tt12\frac{{mv_1^2t}}{{t_1^2}}) is correct because the instantaneous power is calculated using P=FvP = Fv, where F=maF = ma and a=v1t1a = \frac{{v_1}}{{t_1}}, leading to the given expression.

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