JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1

\lim _{x \rightarrow 0}\left[\frac{1}{x} \operatorname{Sin}^{-1}\left(\frac{2 x}{1+x^2}\right)\right]=

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Correct option: C

Option C (2) is correct because after using the identity Sin⁻¹(2x/(1+x²)) = 2Tan⁻¹(x) and simplifying, the limit as x approaches 0 is 2.

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