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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
Let f(x)=x2,g(x)=cos⁡xf(x)=x^2, g(x)=\cos x and h(x)=f(g(x))h(x)=f(g(x)). Area bounded by y=h(x)y=h(x) and yy-axis between x=x1x=x_1 and x=x2x=x_2, where x1x_1 and x2x_2 are roots of the equation 18x2−9πx+π2=018 x^2-9 \pi x+\pi^2=0, is equal to
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Correct option: A
π12\frac{\pi}{12} sq. units
Option A is correct because it represents the area calculated by integrating cos²(x) from π/6 to π/3.

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