JEE PHYSICS MCQ: RAY OPTICS

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Application +4 | -1

Angle of minimum deviation for a prism of refractive index

\mathrm{1}\mathrm{.5}

is equal to the angle of the prism. The angle of the prism is

\left( {\mathrm{given}\,\,\cos \,\,41^\circ \mathrm{\;} - \mathrm{\;}{{24}^\mathrm{'}} - \mathrm{\;}{{36}^{\mathrm{''}}} = \mathrm{\;}0.75} \right)

View answer and explanation

Correct option: A

82^\circ - 49' - 12''

Option A (

82^\circ - 49' - 12''

) is correct because it is derived from using the refractive index formula and the given cosine value to find the prism angle.

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