JEE MATHEMATICS MCQ: BINOMIAL THEOREM

1 Easy

1 of 1

Application +4 | -1

If the coefficient of

rth

\left( {r + 1} \right)th

and

\left( {r + 2} \right)th

terms in the binomial expansion of

{(1 + y)^m}

are in AP, then

m

and

r

satisfy the equation

View answer and explanation

Correct option: B

{m^2} - m\left( {4r + 1} \right) + 4{r^2} - 2 = 0

Option B (

{m^2} - m\left( {4r + 1} \right) + 4{r^2} - 2 = 0

) is correct because it is derived from the condition that the coefficients of the given terms are in Arithmetic Progression (AP).

More Questions from BINOMIAL THEOREM

Practice All Chapter MCQs →

\left({ }^{10} C_0\right)^2-\left({ }^{10} C_1\right)^2+\ldots-\left({ }^{10} C_9\right)^2+\left({ }^{10} C_{10}\right)^2

a

d

\left( {n + 1} \right)

a{C_0} - \left( {a + d} \right){C_1} + \left( {a + 2d} \right){C_2} - ... + ...

(1-x)^{201}\left(1+x+x^2\right)^{200}

\left(\frac{1}{x}+2 x\right)^n

{x^5}

\frac{{1 + {x^2}}}{{1 + x}},\left| x \right| < 1,

\left(\begin{array}{c}2 n+1 \\ 0\end{array}\right)+\left(\begin{array}{c}2 n+1 \\ 3\end{array}\right)+\left(\begin{array}{c}2 n+1 \\ 6\end{array}\right)+\ldots=170

n