JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Analyzing +4 | -1

A physical quantity

P=\frac{\sqrt{a b c^2}}{d^3}

is determined by measuring

a, b, c

, and

d

separately with the percentage error of

2 \%, 3 \%, 2 \%

, and

1 \%

, respectively. Minimum amount of error is contributed by:

View answer and explanation

Correct option: B

a

Option B (

a

) is correct because the percentage error in

P

depends on the error in

a, b, c,

and

d

, and the contribution from

a

is the smallest.

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