JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

The value of

\int\limits_{0}^{2 \pi} \cos ^{-1}\left(\frac{1-\tan ^2 \frac{x}{2}}{1+\tan ^2 \frac{x}{2}}\right) d x

is:

View answer and explanation

Correct option: A

\pi^2

Option A (

\pi^2

) is correct because the integral simplifies to

\int_0^{2 \pi} x dx

, which evaluates to

\pi^2

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