JEE MATHEMATICS MCQ: ELLIPSE

1 Easy

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Application +4 | -1

The locus of the mid-point of the line segment joining the point (4, 3) and the points on the ellipse

{x^2} + 2{y^2} = 4

is an ellipse with eccentricity:

View answer and explanation

Correct option: C

\frac{1}{{\sqrt 2 }}

Option C (

\frac{1}{{\sqrt 2 }}

) is correct because after finding the locus of the midpoint and identifying it as an ellipse, its eccentricity is calculated as

\frac{1}{\sqrt{2}}

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