NEET UG PHYSICS MCQ: SEMI CONDUCTOR DEVICES

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Application +4 | -1

In a common emitter transistor amplifier

\mathrm{\beta } = 60,\;{R_0} = 5000\mathrm{\Omega }

and internal resistance of a transistor is

500\mathrm{\Omega }

. The voltage amplification of amplifier will be

View answer and explanation

Correct option: C

600

Option C (600) is correct because it is the voltage amplification calculated using the given parameters in a common emitter transistor amplifier.

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I = A{T^2}{e^{q/{V_L}}}

{V_L}

\sqrt{n}.

n

p - n\;

{10^{17}}\mathrm{c}{\mathrm{m}^{ - 3}}

P

{10^{16}}

\mathrm{c}{\mathrm{m}^{ - 3}}

N

kT =

{n_i} = 1.4 \times {10^{10}}

\mathrm{c}{\mathrm{m}^{ - 3}}