JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1

1,{\log _9}\left( {{3^{1 - x}} + 2} \right),{\log _3}\left( {{{4.3}^x} - 1} \right)

are in A.P., then

x

equals

View answer and explanation

Correct option: B

1 - {\log _3}4

Option B (

1 - {\log _3}4

) is correct because it is the solution obtained by setting up the A.P. condition and solving the resulting exponential equation.

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A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

(B \cup C)-A

a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

Q(y)=a_0+a_1 y+\ldots+a_{2012} y^{2012}

y=x-2

\sum\limits_{{i=0}}^{2012} a_i

\log \left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)

\log \left(\frac{a}{3 b}\right)

A P

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G P

a, b, c

\frac{3}{4}