JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1

\log _6 a+\log _6 b+\log _6 c=6,

where

a, b, c \in N

and

a, b, c

are in GP and

b-a

is a square of an integer, then the value of

a+b-c

View answer and explanation

Correct option: B

Option B (15) is correct because by using the given conditions and solving for a, b, and c, we find a=27, b=36, and c=48, resulting in a+b-c = 15.

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A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

(B \cup C)-A

a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

Q(y)=a_0+a_1 y+\ldots+a_{2012} y^{2012}

y=x-2

\sum\limits_{{i=0}}^{2012} a_i

\log \left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)

\log \left(\frac{a}{3 b}\right)

A P

a, b

G P

a, b, c

\frac{3}{4}