JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Analyzing +4 | -1

f(x)=0

is a quadratic equation such that

f(-\pi)=f(\pi)=0

and

f\left(\frac{\pi}{2}\right)=-\frac{3 \pi^2}{4}

, then

\lim \limits_{{x \rightarrow-\pi}} \frac{f(x)}{\sin (\sin x)}

, is equal to

View answer and explanation

Correct option: C

2 \pi

Option C (

2 \pi

) is correct because after applying L'Hopital's rule and simplifying, the limit evaluates to

2 \pi

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