The uncertainty in momentum of an electron is $1 \times {10^{ - 5}}$ 1×10-5 kg m/s. the uncertainty in its position will be $(h = 6.62 \times {10^{ - 34}}$ (h=6.62×10-34 kg ${{\bf{m}}^2}/{\bf{s}})$ m2/s)

2.36 <span style='font-size:11.0pt;font-family: "Cambria Math","serif";mso-fareast-font-family:"Times New Roman";mso-bidi-font-family: "Times New Roman";mso-ansi-language:EN-US

Back to STRUCTURE OF ATOM

JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

1 Hard

1 of 1

Application +4 | -1

The uncertainty in momentum of an electron is

1 \times {10^{ - 5}}

 kg m/s. the uncertainty in its position will be 

(h = 6.62 \times {10^{ - 34}}

{\mathbf{m}^2}/\mathbf{s})

View answer and explanation

Correct option: B

5.25

\times {10^{ - 30}}

Option B (5.25

\times {10^{ - 30}}

m) is correct because it is the result of applying the Heisenberg uncertainty principle with the given uncertainty in momentum.

More Questions from STRUCTURE OF ATOM

Practice All Chapter MCQs →

Which of the following is paramagnetic? The time taken by the electron in one complete revolution in the

n^{\text {th }}

Bohr's orbit of the hydrogen atom is The candela is the luminous intensity, in a given direction, of a source that emits monochromatic radiation of frequency '

\mathrm{A}

\times 10^{12}

hertz and that has a radiant intensity in that direction of

\frac{1}{{ }^{\prime} \mathrm{B}^{\prime}}

watt per steradian. 'A' and 'B' are respectively Quantum number which defines the orientation of orbital present in a subshell is Maximum number of electrons associated with

\ell = 1,\,\,m = 0

in magnesium atom is The nucleus and an atom can be assumed to be spherical. The radius of the nucleus of mass no. A is given by

1.25 \times {10^{ - 13}} \times {A^{1/3}}\mathrm{cm}.

. The atomic radius of atom is 1 Å. If the mass no. is 64, the fraction of the atomic volume that is occupied by nucleus is: